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Glasgow | Prati Amalden | Module Complexity | Sprint 2 | Improve with caching #66
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -1,4 +1,12 @@ | ||
| _fib_cache = {} | ||
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| def fibonacci(n): | ||
| if n in _fib_cache: | ||
| return _fib_cache[n] | ||
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| if n <= 1: | ||
| return n | ||
| return fibonacci(n - 1) + fibonacci(n - 2) | ||
| x = n | ||
| else: | ||
| x = fibonacci(n - 1) + fibonacci(n - 2) | ||
| _fib_cache[n] = x | ||
| return x |
41 changes: 25 additions & 16 deletions
41
Sprint-2/improve_with_caches/making_change/making_change.py
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -1,32 +1,41 @@ | ||
| from typing import List | ||
|
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| # cache dictionary, key is (total, tuple_of_coins) | ||
| _change_cache = {} | ||
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| def ways_to_make_change(total: int) -> int: | ||
| """ | ||
| Given access to coins with the values 1, 2, 5, 10, 20, 50, 100, 200, returns a count of all of the ways to make the passed total value. | ||
| For instance, there are two ways to make a value of 3: with 3x 1 coins, or with 1x 1 coin and 1x 2 coin. | ||
| """ | ||
| return ways_to_make_change_helper(total, [200, 100, 50, 20, 10, 5, 2, 1]) | ||
| _change_cache.clear() | ||
| coins = (200, 100, 50, 20, 10, 5, 2, 1) | ||
| return ways_to_make_change_helper(total, tuple(coins)) | ||
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| def ways_to_make_change_helper(total: int, coins: List[int]) -> int: | ||
| def ways_to_make_change_helper(total: int, coins: tuple) -> int: | ||
| """ | ||
| Helper function for ways_to_make_change to avoid exposing the coins parameter to callers. | ||
| """ | ||
| if total == 0 or len(coins) == 0: | ||
| if total == 0: | ||
| return 1 | ||
| if not coins: | ||
| return 0 | ||
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| key = (total, coins) | ||
| if key in _change_cache: | ||
| return _change_cache[key] | ||
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| coin = coins[0] | ||
| rest = coins[1:] | ||
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| ways = 0 | ||
| for coin_index in range(len(coins)): | ||
| coin = coins[coin_index] | ||
| count_of_coin = 1 | ||
| while coin * count_of_coin <= total: | ||
| total_from_coins = coin * count_of_coin | ||
| if total_from_coins == total: | ||
| ways += 1 | ||
| else: | ||
| intermediate = ways_to_make_change_helper(total - total_from_coins, coins=coins[coin_index+1:]) | ||
| ways += intermediate | ||
| count_of_coin += 1 | ||
| count_of_coin = 0 | ||
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| while coin * count_of_coin <= total: | ||
| total_from_coins = coin * count_of_coin | ||
| intermediate = ways_to_make_change_helper(total - total_from_coins, rest) | ||
| ways += intermediate | ||
| count_of_coin += 1 | ||
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| _change_cache[key] = ways | ||
|
Comment on lines
+32
to
+40
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Great job in identifying that we could get rid of the outer for loop. |
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| return ways | ||
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From line 29, we could identify
coinscan only be one of the following 9 tuples:We could further improve the performance if we can
keyas (total, an_integer_that_map_to_the_subtuple) instead of as (total, tuple of coins)I don't think this exercise expects trainees to optimize the code to this level. So change is optional.