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12 changes: 10 additions & 2 deletions Sprint-2/improve_with_caches/fibonacci/fibonacci.py
Original file line number Diff line number Diff line change
@@ -1,4 +1,12 @@
_fib_cache = {}

def fibonacci(n):
if n in _fib_cache:
return _fib_cache[n]

if n <= 1:
return n
return fibonacci(n - 1) + fibonacci(n - 2)
x = n
else:
x = fibonacci(n - 1) + fibonacci(n - 2)
_fib_cache[n] = x
return x
41 changes: 25 additions & 16 deletions Sprint-2/improve_with_caches/making_change/making_change.py
Original file line number Diff line number Diff line change
@@ -1,32 +1,41 @@
from typing import List

# cache dictionary, key is (total, tuple_of_coins)
_change_cache = {}

def ways_to_make_change(total: int) -> int:
"""
Given access to coins with the values 1, 2, 5, 10, 20, 50, 100, 200, returns a count of all of the ways to make the passed total value.
For instance, there are two ways to make a value of 3: with 3x 1 coins, or with 1x 1 coin and 1x 2 coin.
"""
return ways_to_make_change_helper(total, [200, 100, 50, 20, 10, 5, 2, 1])
_change_cache.clear()
coins = (200, 100, 50, 20, 10, 5, 2, 1)
return ways_to_make_change_helper(total, tuple(coins))


def ways_to_make_change_helper(total: int, coins: List[int]) -> int:
def ways_to_make_change_helper(total: int, coins: tuple) -> int:
"""
Helper function for ways_to_make_change to avoid exposing the coins parameter to callers.
"""
if total == 0 or len(coins) == 0:
if total == 0:
return 1
if not coins:
return 0

key = (total, coins)
if key in _change_cache:
return _change_cache[key]

coin = coins[0]
rest = coins[1:]
Comment on lines +24 to +29
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From line 29, we could identify coins can only be one of the following 9 tuples:

(200, 100, 50, 20, 10, 5, 2, 1)
(100, 50, 20, 10, 5, 2, 1)
(50, 20, 10, 5, 2, 1)
...
(1)
()

We could further improve the performance if we can

  • avoid repeatedly creating the same sub-tuples at line 29 (e.g. use another cache), and
  • create key as (total, an_integer_that_map_to_the_subtuple) instead of as (total, tuple of coins)

I don't think this exercise expects trainees to optimize the code to this level. So change is optional.


ways = 0
for coin_index in range(len(coins)):
coin = coins[coin_index]
count_of_coin = 1
while coin * count_of_coin <= total:
total_from_coins = coin * count_of_coin
if total_from_coins == total:
ways += 1
else:
intermediate = ways_to_make_change_helper(total - total_from_coins, coins=coins[coin_index+1:])
ways += intermediate
count_of_coin += 1
count_of_coin = 0

while coin * count_of_coin <= total:
total_from_coins = coin * count_of_coin
intermediate = ways_to_make_change_helper(total - total_from_coins, rest)
ways += intermediate
count_of_coin += 1

_change_cache[key] = ways
Comment on lines +32 to +40
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Great job in identifying that we could get rid of the outer for loop.

return ways
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